What are the zeros of the quadratic function f(x) = 6x2 – 24x + 1?

The zeros or roots of the quadratic function f(x) = 6x² – 24x +1 were found with the help of the formula.The given quadratic equation is:[tex]6x^{2} -24x+1=0[/tex]What is a quadratic equation?Any equation of the form [tex]ax^{2} +bx+c=0[/tex] where a≠0 is called a quadratic equation.We know the solution of a quadratic equation [tex]ax^{2} +bx+c=0[/tex] is given by:[tex]x=\frac{-b +\sqrt{b^{2}-4ac } }{2a}[/tex][tex]x=\frac{-b -\sqrt{b^{2}-4ac } }{2a}[/tex]So, the solution of the quadratic equation [tex]6x^{2} -24x+1=0[/tex] will be:[tex]x=\frac{-(-24) +\sqrt{(-24)^{2}-4(6)(1) } }{2*6}[/tex][tex]x=\frac{12+\sqrt{138} }{6}[/tex][tex]x=\frac{12-\sqrt{138} }{6}[/tex]Thus, the zeros or roots of the quadratic function f(x) = 6x² – 24x +1 were found with the help of the formula.To get more about quadratic equations visit: