MATH SOLVE

4 months ago

Q:
# (3 points) A survey of 15651565 people who took trips revealed that 178178 of them included a visit to a theme park. Based on those survery results, a management consultant claims that less than 1212 % of trips include a theme park visit. Test this claim using the α=0.05α=0.05 significance level.

Accepted Solution

A:

Answer:We fail to reject the null hypothesis at 0.05 significance level. We cannot say that less than 12% of trips include a theme park visit. Step-by-step explanation:let p be the proportion of trips included a visit to a theme park.[tex]H_{0}[/tex]: p=0.12[tex]H_{a}[/tex]: p<0.12To test, we need to calculate test statistic of the sample proportion as:z=[tex]\frac{p(s)-p}{\sqrt{\frac{p*(1-p)}{N} } }[/tex] where p(s) is the sample proportion of trips included visit to a theme park ([tex]\frac{178}{1565}=0.1137[/tex]p is the proportion assumed under null hypothesis. (0.12)N is the sample size (1565)Using the numbers, z=[tex]\frac{0.1137-0.12}{\sqrt{\frac{0.12*0.88}{1565}}}[/tex] = −0.767 and p(z) is ≈0.222 Since 0.222 > 0.05 we fail to reject the null hypothesis.