The point slope form of the eqaution of the line that passes through (-5,-1) and (10, -7) is y+7= -2/5 (x - 10) what is the standard form of the equation for this line 2x-5y=-15 2x-5y= -17 2x+5y=-15 2x+5y=-17

Accepted Solution

Answer:2x + 5y = -15Step-by-step explanation:The standard form of an equation of a line:[tex]Ax+By=C[/tex]We have the equation in point-slope form:[tex]y+7=-\dfrac{2}{5}(x-10)[/tex]Convert it to the standard form:[tex]y+7=-\dfrac{2}{5}(x-10)[/tex]     multiply both sides by 5[tex]5y+35=-2(x-10)[/tex]         use the distributive property a(b + c) = ab + ac[tex]5y+35=(-2)(x)+(-2)(-10)[/tex][tex]5y+35=-2x+20[/tex]          subtract 35 from both sides[tex]5y=-2x-15[/tex]            add 2x to both sides[tex]2x+5y=-15[/tex]