If we try to evaluate this expression, we arrive at an indeterminate limit of the form ∞ · 0. So we rewrite this limit as lim of [ e^(-x/5) / (1 / x^3) ] as x→∞ This results in an determinate form of 0/0, so we apply L'Hospital's rule by differentiating the numerator and denominator. lim of [ -1/5e^(-x/5) / (-3/x^4) ] as x→∞ Multiply the numerator and denominator by x^4 lim of [ -1/5 * x^4 * e^(-x/5) / (-3) ] as x→∞ Since e^(-x/5) approaches 0 as x→∞, the limit evaluates to 0. The answer to this question is 0.